Optimal. Leaf size=180 \[ -\frac{b^2 \text{PolyLog}\left (2,\frac{2}{c+d x+1}-1\right )}{3 d e^4}-\frac{b \left (a+b \tanh ^{-1}(c+d x)\right )}{3 d e^4 (c+d x)^2}-\frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{3 d e^4 (c+d x)^3}+\frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{3 d e^4}+\frac{2 b \log \left (2-\frac{2}{c+d x+1}\right ) \left (a+b \tanh ^{-1}(c+d x)\right )}{3 d e^4}-\frac{b^2}{3 d e^4 (c+d x)}+\frac{b^2 \tanh ^{-1}(c+d x)}{3 d e^4} \]
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Rubi [A] time = 0.270127, antiderivative size = 180, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 9, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.391, Rules used = {6107, 12, 5916, 5982, 325, 206, 5988, 5932, 2447} \[ -\frac{b^2 \text{PolyLog}\left (2,\frac{2}{c+d x+1}-1\right )}{3 d e^4}-\frac{b \left (a+b \tanh ^{-1}(c+d x)\right )}{3 d e^4 (c+d x)^2}-\frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{3 d e^4 (c+d x)^3}+\frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{3 d e^4}+\frac{2 b \log \left (2-\frac{2}{c+d x+1}\right ) \left (a+b \tanh ^{-1}(c+d x)\right )}{3 d e^4}-\frac{b^2}{3 d e^4 (c+d x)}+\frac{b^2 \tanh ^{-1}(c+d x)}{3 d e^4} \]
Antiderivative was successfully verified.
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Rule 6107
Rule 12
Rule 5916
Rule 5982
Rule 325
Rule 206
Rule 5988
Rule 5932
Rule 2447
Rubi steps
\begin{align*} \int \frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{(c e+d e x)^4} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (a+b \tanh ^{-1}(x)\right )^2}{e^4 x^4} \, dx,x,c+d x\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \frac{\left (a+b \tanh ^{-1}(x)\right )^2}{x^4} \, dx,x,c+d x\right )}{d e^4}\\ &=-\frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{3 d e^4 (c+d x)^3}+\frac{(2 b) \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(x)}{x^3 \left (1-x^2\right )} \, dx,x,c+d x\right )}{3 d e^4}\\ &=-\frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{3 d e^4 (c+d x)^3}+\frac{(2 b) \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(x)}{x^3} \, dx,x,c+d x\right )}{3 d e^4}+\frac{(2 b) \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(x)}{x \left (1-x^2\right )} \, dx,x,c+d x\right )}{3 d e^4}\\ &=-\frac{b \left (a+b \tanh ^{-1}(c+d x)\right )}{3 d e^4 (c+d x)^2}+\frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{3 d e^4}-\frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{3 d e^4 (c+d x)^3}+\frac{(2 b) \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(x)}{x (1+x)} \, dx,x,c+d x\right )}{3 d e^4}+\frac{b^2 \operatorname{Subst}\left (\int \frac{1}{x^2 \left (1-x^2\right )} \, dx,x,c+d x\right )}{3 d e^4}\\ &=-\frac{b^2}{3 d e^4 (c+d x)}-\frac{b \left (a+b \tanh ^{-1}(c+d x)\right )}{3 d e^4 (c+d x)^2}+\frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{3 d e^4}-\frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{3 d e^4 (c+d x)^3}+\frac{2 b \left (a+b \tanh ^{-1}(c+d x)\right ) \log \left (2-\frac{2}{1+c+d x}\right )}{3 d e^4}+\frac{b^2 \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,c+d x\right )}{3 d e^4}-\frac{\left (2 b^2\right ) \operatorname{Subst}\left (\int \frac{\log \left (2-\frac{2}{1+x}\right )}{1-x^2} \, dx,x,c+d x\right )}{3 d e^4}\\ &=-\frac{b^2}{3 d e^4 (c+d x)}+\frac{b^2 \tanh ^{-1}(c+d x)}{3 d e^4}-\frac{b \left (a+b \tanh ^{-1}(c+d x)\right )}{3 d e^4 (c+d x)^2}+\frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{3 d e^4}-\frac{\left (a+b \tanh ^{-1}(c+d x)\right )^2}{3 d e^4 (c+d x)^3}+\frac{2 b \left (a+b \tanh ^{-1}(c+d x)\right ) \log \left (2-\frac{2}{1+c+d x}\right )}{3 d e^4}-\frac{b^2 \text{Li}_2\left (-1+\frac{2}{1+c+d x}\right )}{3 d e^4}\\ \end{align*}
Mathematica [A] time = 0.534509, size = 218, normalized size = 1.21 \[ -\frac{b^2 \left ((c+d x)^3 \text{PolyLog}\left (2,e^{-2 \tanh ^{-1}(c+d x)}\right )+(c+d x)^2+(c+d x)^2 \tanh ^{-1}(c+d x)^2+\left (1-(c+d x)^2\right ) \tanh ^{-1}(c+d x)^2+(c+d x) \tanh ^{-1}(c+d x) \left (-(c+d x)^2+(c+d x)^2 \left (-\tanh ^{-1}(c+d x)\right )-2 (c+d x)^2 \log \left (1-e^{-2 \tanh ^{-1}(c+d x)}\right )+1\right )\right )+a^2-a b \left ((c+d x) \left (c^2+2 c d x+2 (c+d x)^2 \log \left (\frac{c+d x}{\sqrt{1-(c+d x)^2}}\right )+d^2 x^2-1\right )-2 \tanh ^{-1}(c+d x)\right )}{3 d e^4 (c+d x)^3} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.066, size = 492, normalized size = 2.7 \begin{align*} -{\frac{{a}^{2}}{3\,d{e}^{4} \left ( dx+c \right ) ^{3}}}-{\frac{{b}^{2} \left ({\it Artanh} \left ( dx+c \right ) \right ) ^{2}}{3\,d{e}^{4} \left ( dx+c \right ) ^{3}}}-{\frac{{b}^{2}{\it Artanh} \left ( dx+c \right ) \ln \left ( dx+c-1 \right ) }{3\,d{e}^{4}}}-{\frac{{b}^{2}{\it Artanh} \left ( dx+c \right ) }{3\,d{e}^{4} \left ( dx+c \right ) ^{2}}}+{\frac{2\,{b}^{2}\ln \left ( dx+c \right ){\it Artanh} \left ( dx+c \right ) }{3\,d{e}^{4}}}-{\frac{{b}^{2}{\it Artanh} \left ( dx+c \right ) \ln \left ( dx+c+1 \right ) }{3\,d{e}^{4}}}-{\frac{{b}^{2}}{3\,d{e}^{4} \left ( dx+c \right ) }}-{\frac{{b}^{2}\ln \left ( dx+c-1 \right ) }{6\,d{e}^{4}}}+{\frac{{b}^{2}\ln \left ( dx+c+1 \right ) }{6\,d{e}^{4}}}-{\frac{{b}^{2} \left ( \ln \left ( dx+c-1 \right ) \right ) ^{2}}{12\,d{e}^{4}}}+{\frac{{b}^{2}}{3\,d{e}^{4}}{\it dilog} \left ({\frac{1}{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) }+{\frac{{b}^{2}\ln \left ( dx+c-1 \right ) }{6\,d{e}^{4}}\ln \left ({\frac{1}{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) }+{\frac{{b}^{2}}{6\,d{e}^{4}}\ln \left ( -{\frac{dx}{2}}-{\frac{c}{2}}+{\frac{1}{2}} \right ) \ln \left ({\frac{1}{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) }-{\frac{{b}^{2}\ln \left ( dx+c+1 \right ) }{6\,d{e}^{4}}\ln \left ( -{\frac{dx}{2}}-{\frac{c}{2}}+{\frac{1}{2}} \right ) }+{\frac{{b}^{2} \left ( \ln \left ( dx+c+1 \right ) \right ) ^{2}}{12\,d{e}^{4}}}-{\frac{{b}^{2}{\it dilog} \left ( dx+c \right ) }{3\,d{e}^{4}}}-{\frac{{b}^{2}{\it dilog} \left ( dx+c+1 \right ) }{3\,d{e}^{4}}}-{\frac{{b}^{2}\ln \left ( dx+c \right ) \ln \left ( dx+c+1 \right ) }{3\,d{e}^{4}}}-{\frac{2\,ab{\it Artanh} \left ( dx+c \right ) }{3\,d{e}^{4} \left ( dx+c \right ) ^{3}}}-{\frac{ab\ln \left ( dx+c-1 \right ) }{3\,d{e}^{4}}}-{\frac{ab}{3\,d{e}^{4} \left ( dx+c \right ) ^{2}}}+{\frac{2\,ab\ln \left ( dx+c \right ) }{3\,d{e}^{4}}}-{\frac{ab\ln \left ( dx+c+1 \right ) }{3\,d{e}^{4}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{3} \,{\left (d{\left (\frac{1}{d^{4} e^{4} x^{2} + 2 \, c d^{3} e^{4} x + c^{2} d^{2} e^{4}} + \frac{\log \left (d x + c + 1\right )}{d^{2} e^{4}} - \frac{2 \, \log \left (d x + c\right )}{d^{2} e^{4}} + \frac{\log \left (d x + c - 1\right )}{d^{2} e^{4}}\right )} + \frac{2 \, \operatorname{artanh}\left (d x + c\right )}{d^{4} e^{4} x^{3} + 3 \, c d^{3} e^{4} x^{2} + 3 \, c^{2} d^{2} e^{4} x + c^{3} d e^{4}}\right )} a b - \frac{1}{12} \, b^{2}{\left (\frac{\log \left (-d x - c + 1\right )^{2}}{d^{4} e^{4} x^{3} + 3 \, c d^{3} e^{4} x^{2} + 3 \, c^{2} d^{2} e^{4} x + c^{3} d e^{4}} + 3 \, \int -\frac{3 \,{\left (d x + c - 1\right )} \log \left (d x + c + 1\right )^{2} + 2 \,{\left (d x - 3 \,{\left (d x + c - 1\right )} \log \left (d x + c + 1\right ) + c\right )} \log \left (-d x - c + 1\right )}{3 \,{\left (d^{5} e^{4} x^{5} + c^{5} e^{4} - c^{4} e^{4} +{\left (5 \, c d^{4} e^{4} - d^{4} e^{4}\right )} x^{4} + 2 \,{\left (5 \, c^{2} d^{3} e^{4} - 2 \, c d^{3} e^{4}\right )} x^{3} + 2 \,{\left (5 \, c^{3} d^{2} e^{4} - 3 \, c^{2} d^{2} e^{4}\right )} x^{2} +{\left (5 \, c^{4} d e^{4} - 4 \, c^{3} d e^{4}\right )} x\right )}}\,{d x}\right )} - \frac{a^{2}}{3 \,{\left (d^{4} e^{4} x^{3} + 3 \, c d^{3} e^{4} x^{2} + 3 \, c^{2} d^{2} e^{4} x + c^{3} d e^{4}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b^{2} \operatorname{artanh}\left (d x + c\right )^{2} + 2 \, a b \operatorname{artanh}\left (d x + c\right ) + a^{2}}{d^{4} e^{4} x^{4} + 4 \, c d^{3} e^{4} x^{3} + 6 \, c^{2} d^{2} e^{4} x^{2} + 4 \, c^{3} d e^{4} x + c^{4} e^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a^{2}}{c^{4} + 4 c^{3} d x + 6 c^{2} d^{2} x^{2} + 4 c d^{3} x^{3} + d^{4} x^{4}}\, dx + \int \frac{b^{2} \operatorname{atanh}^{2}{\left (c + d x \right )}}{c^{4} + 4 c^{3} d x + 6 c^{2} d^{2} x^{2} + 4 c d^{3} x^{3} + d^{4} x^{4}}\, dx + \int \frac{2 a b \operatorname{atanh}{\left (c + d x \right )}}{c^{4} + 4 c^{3} d x + 6 c^{2} d^{2} x^{2} + 4 c d^{3} x^{3} + d^{4} x^{4}}\, dx}{e^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{artanh}\left (d x + c\right ) + a\right )}^{2}}{{\left (d e x + c e\right )}^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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